24-28x-12x^2=0

Solution for 24-28x-12x^2=0 equation:

24-28x-12x^2=0

a = -12; b = -28; c = +24;
Δ = b2-4ac
Δ = -282-4·(-12)·24
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-44}{2*-12}=\frac{-16}{-24}
=2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+44}{2*-12}=\frac{72}{-24}
=-3
$